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  • 杀人的眼神
    ChoCoChips's Avatar
    6,370 posts since Jun '06
  • ispyyy's Avatar
    5,486 posts since May '07
    • lol... try ah...

      Input Voltage

      = 240( sin 2*pi*50 + jcos 2*pi*50)

      = 240( -0.26 +j0.96)

      = -62.4 +j230.4

      Total input impedence

      = 1/(1/z1 + 1/z2 + 1/z3)

      =2.33+j1.1

      Total current

      = Total voltage/Total impedence

      = 16.27+j91.2

      Total input power

      =| Re {VI} |= 22028

      Total reactant power

      = | Img {VI} | = 1941

       

      jwC + 1/Zin = Re number

      Hence,

      if 1/Zin = 0.35-j0.17,

      jwC = j0.17

      C = 5.4x 10E-4 F

       

       

       

  • ispyyy's Avatar
    5,486 posts since May '07
    • I forgot on the power fomular...

      Dont noe it is the real number of whole answer or real number x real number....

      hahaahaha...

      Check it out yrself lor...

      :p

       

  • 杀人的眼神
    ChoCoChips's Avatar
    6,370 posts since Jun '06
  • ispyyy's Avatar
    5,486 posts since May '07
    • Originally posted by ChoCoChips:

      die.

      i got different values leh.

      hahaha chui liao la me

       

      who noes???

      u maybe correct lor...

      I long long long long long time never do this type of question liao... :p

       

  • 杀人的眼神
    ChoCoChips's Avatar
    6,370 posts since Jun '06
    • eh and hor,

      why input voltage ish got the cos and sin one?

      i tot it's just 240v and 0 degrees only?

  • ispyyy's Avatar
    5,486 posts since May '07
    • Originally posted by ChoCoChips:

      eh and hor,

      why input voltage ish got the cos and sin one?

      i tot it's just 240v and 0 degrees only?

      oh ya hor... me mess up liao...

      hahahaaa... it is 240V with 0 degrees...

      :p

       

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