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    <title>Recent Posts in 'Physics - Pressure' | sgForums.com</title>
    <link>http://politics.sgforums.com/forums/2297/topics/324678</link>
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      <title>Physics - Pressure replied by eagle @ Fri, 25 Jul 2008 00:06:32 +0800</title>
      <description>&lt;blockquote&gt;
&lt;div class="quote_from"&gt;Originally posted by bonkysleuth:&lt;/div&gt;
&lt;div class="quote_body"&gt;
&lt;p&gt;&lt;br /&gt;
Thanks. But I somehow dont get this part:&lt;/p&gt;
&lt;p&gt;&amp;nbsp;&lt;/p&gt;
&lt;p&gt;if the small cube has weight w, the large cube has weight 8w,
since weight is proportional to volume (same material means same
density).&lt;/p&gt;
&lt;p&gt;Thus, pressure exerted by larger cube = 8w / 4a = 2 w/a = 2p&lt;/p&gt;
&lt;p&gt;&amp;nbsp;&lt;/p&gt;
&lt;p&gt;i still dont know why weight is proportional to volume. havent
heard of that before.&lt;/p&gt;
&lt;p&gt;&amp;nbsp;&lt;/p&gt;
&lt;/div&gt;
&lt;/blockquote&gt;
&lt;p&gt;Ok.&lt;/p&gt;
&lt;p&gt;One of the ways to see it is:&lt;/p&gt;
&lt;p&gt;Weight is proportional to mass.&lt;br /&gt;
Mass is proportional to volume (since mass = density * volume)&lt;/p&gt;
&lt;p&gt;Therefore, Weight is proportional to volume.&lt;/p&gt;</description>
      <pubDate>Fri, 25 Jul 2008 00:06:32 +0800</pubDate>
      <guid isPermaLink="false">politics.sgforums.com:2297:324678:8264274</guid>
      <author>eagle</author>
      <link>http://politics.sgforums.com/forums/2297/topics/324678</link>
    </item>
    <item>
      <title>Physics - Pressure replied by bonkysleuth @ Thu, 24 Jul 2008 21:07:09 +0800</title>
      <description>&lt;blockquote&gt;
&lt;div class="quote_from"&gt;Originally posted by eagle:&lt;/div&gt;
&lt;div class="quote_body"&gt;
&lt;p&gt;if the small cube has face area a, the large cube has area
4a.&lt;/p&gt;
&lt;p&gt;Also, if the small cube has weight w, the large cube has weight
8w, since weight is proportional to volume (same material means
same density).&lt;/p&gt;
&lt;p&gt;Thus, pressure exerted by larger cube = 8w / 4a = 2 w/a = 2p&lt;/p&gt;
&lt;/div&gt;
&lt;/blockquote&gt;
&lt;p&gt;&lt;br /&gt;
Thanks. But I somehow dont get this part:&lt;/p&gt;
&lt;p&gt;&amp;nbsp;&lt;/p&gt;
&lt;p&gt;if the small cube has weight w, the large cube has weight 8w,
since weight is proportional to volume (same material means same
density).&lt;/p&gt;
&lt;p&gt;Thus, pressure exerted by larger cube = 8w / 4a = 2 w/a = 2p&lt;/p&gt;
&lt;p&gt;&amp;nbsp;&lt;/p&gt;
&lt;p&gt;i still dont know why weight is proportional to volume. havent
heard of that before.&lt;/p&gt;
&lt;p&gt;&amp;nbsp;&lt;/p&gt;</description>
      <pubDate>Thu, 24 Jul 2008 21:07:09 +0800</pubDate>
      <guid isPermaLink="false">politics.sgforums.com:2297:324678:8263771</guid>
      <author>bonkysleuth</author>
      <link>http://politics.sgforums.com/forums/2297/topics/324678</link>
    </item>
    <item>
      <title>Physics - Pressure replied by eagle @ Mon, 21 Jul 2008 17:01:39 +0800</title>
      <description>&lt;blockquote&gt;
&lt;div class="quote_from"&gt;Originally posted by bonkysleuth:&lt;/div&gt;
&lt;div class="quote_body"&gt;
&lt;p&gt;Oh yea and there's this question from the Ten Years series.&lt;/p&gt;
&lt;p&gt;&amp;nbsp;&lt;/p&gt;
&lt;p&gt;2 cubes are made form the same material. one cube has sides that
are twice as long as the other. standing on one face, the small
cube exerts a pressure p = w/a, where a is the area of the face.
what is the pressure exerted by the larger cube standing on ONE of
its faces?&lt;/p&gt;
&lt;p&gt;&amp;nbsp;&lt;/p&gt;
&lt;p&gt;I got this answer as 4p but the answer booklet writes 2p. can
anyone explain?&lt;/p&gt;
&lt;/div&gt;
&lt;/blockquote&gt;
&lt;p&gt;if the small cube has face area a, the large cube has area
4a.&lt;/p&gt;
&lt;p&gt;Also, if the small cube has weight w, the large cube has weight
8w, since weight is proportional to volume (same material means
same density).&lt;/p&gt;
&lt;p&gt;Thus, pressure exerted by larger cube = 8w / 4a = 2 w/a = 2p&lt;/p&gt;</description>
      <pubDate>Mon, 21 Jul 2008 17:01:39 +0800</pubDate>
      <guid isPermaLink="false">politics.sgforums.com:2297:324678:8256446</guid>
      <author>eagle</author>
      <link>http://politics.sgforums.com/forums/2297/topics/324678</link>
    </item>
    <item>
      <title>Physics - Pressure replied by eagle @ Mon, 21 Jul 2008 16:59:44 +0800</title>
      <description>&lt;blockquote&gt;
&lt;div class="quote_from"&gt;Originally posted by bonkysleuth:&lt;/div&gt;
&lt;div class="quote_body"&gt;
&lt;p&gt;&lt;br /&gt;
So how do you get 1 atm and 3atm? I don't understand this because I
havent learnt this before. But I am interested to find out.&lt;/p&gt;
&lt;/div&gt;
&lt;/blockquote&gt;
&lt;p&gt;1 atm is pressure at the water surface. That's because it is the
air pressure.&lt;/p&gt;
&lt;p&gt;and at depth of 20m, the total pressure comes from 1atm (at
water surface) + 20m of water. Since 10m of water = 1atm, that
means total pressure = 3atm&lt;/p&gt;
&lt;p&gt;&amp;nbsp;&lt;/p&gt;</description>
      <pubDate>Mon, 21 Jul 2008 16:59:44 +0800</pubDate>
      <guid isPermaLink="false">politics.sgforums.com:2297:324678:8256443</guid>
      <author>eagle</author>
      <link>http://politics.sgforums.com/forums/2297/topics/324678</link>
    </item>
    <item>
      <title>Physics - Pressure replied by bonkysleuth @ Mon, 21 Jul 2008 16:38:17 +0800</title>
      <description>&lt;p&gt;Oh yea and there's this question from the Ten Years series.&lt;/p&gt;
&lt;p&gt;&amp;nbsp;&lt;/p&gt;
&lt;p&gt;2 cubes are made form the same material. one cube has sides that
are twice as long as the other. standing on one face, the small
cube exerts a pressure p = w/a, where a is the area of the face.
what is the pressure exerted by the larger cube standing on ONE of
its faces?&lt;/p&gt;
&lt;p&gt;&amp;nbsp;&lt;/p&gt;
&lt;p&gt;I got this answer as 4p but the answer booklet writes 2p. can
anyone explain?&lt;/p&gt;</description>
      <pubDate>Mon, 21 Jul 2008 16:38:17 +0800</pubDate>
      <guid isPermaLink="false">politics.sgforums.com:2297:324678:8256414</guid>
      <author>bonkysleuth</author>
      <link>http://politics.sgforums.com/forums/2297/topics/324678</link>
    </item>
    <item>
      <title>Physics - Pressure replied by bonkysleuth @ Mon, 21 Jul 2008 16:36:26 +0800</title>
      <description>&lt;blockquote&gt;
&lt;div class="quote_from"&gt;Originally posted by eagle:&lt;/div&gt;
&lt;div class="quote_body"&gt;
&lt;p&gt;the equation means this&lt;/p&gt;
&lt;p&gt;original volume multiplied by original pressure equals to final
volume multiplied by final pressure&lt;/p&gt;
&lt;p&gt;or vice versa&lt;/p&gt;
&lt;p&gt;Do you understand the above part first? Understand then we
proceed to the next step&lt;/p&gt;
&lt;/div&gt;
&lt;/blockquote&gt;
&lt;p&gt;&lt;br /&gt;
So how do you get 1 atm and 3atm? I don't understand this because I
havent learnt this before. But I am interested to find out.&lt;/p&gt;</description>
      <pubDate>Mon, 21 Jul 2008 16:36:26 +0800</pubDate>
      <guid isPermaLink="false">politics.sgforums.com:2297:324678:8256407</guid>
      <author>bonkysleuth</author>
      <link>http://politics.sgforums.com/forums/2297/topics/324678</link>
    </item>
    <item>
      <title>Physics - Pressure replied by UltimaOnline @ Sun, 20 Jul 2008 16:21:58 +0800</title>
      <description>&lt;p&gt;This qn also appears&amp;nbsp;similar to my "Loch Ness Monster" qn,
although mine is surely a lot more interesting! &lt;img src=
"/images/emoticons/kde-3.5.8/redones/angel.png" alt=
"angel.png" /&gt;&lt;/p&gt;
&lt;p&gt;&amp;nbsp;&lt;/p&gt;
&lt;p&gt;See the most recent at the bottom of my "'O'&amp;amp;'A' Lvls
Balancing Equation &amp;amp; Stoichiometry Practice Qns" stickied
thread :&lt;/p&gt;
&lt;p&gt;&lt;a href="http://www.sgforums.com/forums/2297/topics/320107" rel=
"nofollow"&gt;http://www.sgforums.com/forums/2297/topics/320107&lt;/a&gt;&lt;/p&gt;</description>
      <pubDate>Sun, 20 Jul 2008 16:21:58 +0800</pubDate>
      <guid isPermaLink="false">politics.sgforums.com:2297:324678:8254391</guid>
      <author>UltimaOnline</author>
      <link>http://politics.sgforums.com/forums/2297/topics/324678</link>
    </item>
    <item>
      <title>Physics - Pressure replied by Darkness_hacker99 @ Sun, 20 Jul 2008 00:54:14 +0800</title>
      <description>&lt;p&gt;P1V1 = P2V2&lt;br /&gt;
&lt;br /&gt;
This formula is taught in your syllabus under the chapter
&lt;em&gt;Pressure&lt;/em&gt;:&lt;span style=
"text-decoration: underline;"&gt;&lt;em&gt;Pressure changes&lt;/em&gt;&lt;/span&gt;.
&lt;img src="/images/emoticons/classic/icon_smile.gif" alt=
"icon_smile.gif" /&gt;&lt;/p&gt;</description>
      <pubDate>Sun, 20 Jul 2008 00:54:14 +0800</pubDate>
      <guid isPermaLink="false">politics.sgforums.com:2297:324678:8253669</guid>
      <author>Darkness_hacker99</author>
      <link>http://politics.sgforums.com/forums/2297/topics/324678</link>
    </item>
    <item>
      <title>Physics - Pressure replied by eagle @ Sun, 20 Jul 2008 00:12:45 +0800</title>
      <description>&lt;p&gt;the equation means this&lt;/p&gt;
&lt;p&gt;original volume multiplied by original pressure equals to final
volume multiplied by final pressure&lt;/p&gt;
&lt;p&gt;or vice versa&lt;/p&gt;
&lt;p&gt;Do you understand the above part first? Understand then we
proceed to the next step&lt;/p&gt;</description>
      <pubDate>Sun, 20 Jul 2008 00:12:45 +0800</pubDate>
      <guid isPermaLink="false">politics.sgforums.com:2297:324678:8253583</guid>
      <author>eagle</author>
      <link>http://politics.sgforums.com/forums/2297/topics/324678</link>
    </item>
    <item>
      <title>Physics - Pressure replied by bonkysleuth @ Sat, 19 Jul 2008 23:22:01 +0800</title>
      <description>&lt;p&gt;In that post Darkness_hacker99 mentioned, eagle posted the
solution as this:&lt;/p&gt;
&lt;p&gt;&amp;nbsp;&lt;/p&gt;
&lt;p&gt;&amp;nbsp;&lt;/p&gt;
&lt;p&gt;&amp;nbsp;at surface:&lt;br /&gt;
pressure, P1 = 1atm (atmospheric pressure equivalent to 10m of
water), V1 = 6cm&lt;span style=
"font-family: Times New Roman;"&gt;&lt;sup&gt;3&lt;/sup&gt;&lt;/span&gt;&lt;/p&gt;
&lt;p&gt;at bottom of lake:&lt;br /&gt;
pressure, P2 = 3 atm (atmospheric pressure + 20m of water), V2 =
unknown&lt;/p&gt;
&lt;p&gt;Using Bolye's Law, P1V1 = P2V2&lt;/p&gt;
&lt;p&gt;V2 = 2cm&lt;span style=
"font-family: Times New Roman;"&gt;&lt;sup&gt;3&lt;/sup&gt;&lt;/span&gt;&lt;/p&gt;
&lt;p&gt;&lt;span style="font-family: Times New Roman;"&gt;&lt;sup&gt;But the thing
is, I haven't learnt about this Boyle's Law thing. Nor have I heard
of it. My brother tried to teach me using this method but he told
me not to attempt this question since I havent been taught about
the law before. why is P1 = 1 atm and P2 = 3 atm?&lt;/sup&gt;&lt;/span&gt;&lt;/p&gt;</description>
      <pubDate>Sat, 19 Jul 2008 23:22:01 +0800</pubDate>
      <guid isPermaLink="false">politics.sgforums.com:2297:324678:8253472</guid>
      <author>bonkysleuth</author>
      <link>http://politics.sgforums.com/forums/2297/topics/324678</link>
    </item>
    <item>
      <title>Physics - Pressure replied by Darkness_hacker99 @ Sat, 19 Jul 2008 23:01:02 +0800</title>
      <description>&lt;p&gt;&lt;a href="/forums/2297/topics/309235" rel=
"nofollow"&gt;http://www.sgforums.com/forums/2297/topics/309235&amp;nbsp;&lt;/a&gt;
&lt;img src="/images/emoticons/classic/icon_lol.gif" alt=
"icon_lol.gif" /&gt;&lt;/p&gt;</description>
      <pubDate>Sat, 19 Jul 2008 23:01:02 +0800</pubDate>
      <guid isPermaLink="false">politics.sgforums.com:2297:324678:8253439</guid>
      <author>Darkness_hacker99</author>
      <link>http://politics.sgforums.com/forums/2297/topics/324678</link>
    </item>
    <item>
      <title>Physics - Pressure replied by Darkness_hacker99 @ Sat, 19 Jul 2008 22:41:34 +0800</title>
      <description>&lt;p&gt;This question looked soooo familiar to me.... o.O As if someone
asked this before...&lt;/p&gt;</description>
      <pubDate>Sat, 19 Jul 2008 22:41:34 +0800</pubDate>
      <guid isPermaLink="false">politics.sgforums.com:2297:324678:8253392</guid>
      <author>Darkness_hacker99</author>
      <link>http://politics.sgforums.com/forums/2297/topics/324678</link>
    </item>
    <item>
      <title>Physics - Pressure replied by jiaxing2 @ Sat, 19 Jul 2008 22:33:29 +0800</title>
      <description>&lt;p&gt;p inversely proportional to &amp;nbsp;v ( same temp)&lt;/p&gt;
&lt;p&gt;p1v1=p2v2&lt;/p&gt;
&lt;p&gt;at bottom pressure = 3 p (atm) compared to 1 atm at the top&lt;/p&gt;
&lt;p&gt;thus V bottom = 6/3 = 2 cm3&lt;/p&gt;
&lt;p&gt;&amp;nbsp;&lt;/p&gt;</description>
      <pubDate>Sat, 19 Jul 2008 22:33:29 +0800</pubDate>
      <guid isPermaLink="false">politics.sgforums.com:2297:324678:8253373</guid>
      <author>jiaxing2</author>
      <link>http://politics.sgforums.com/forums/2297/topics/324678</link>
    </item>
    <item>
      <title>Physics - Pressure replied by bonkysleuth @ Sat, 19 Jul 2008 22:04:54 +0800</title>
      <description>&lt;p&gt;Water of depth 10 m exerts a pressure equal to atmospheric
pressure. An air bubble rises to te surface of a lake which is 20 m
deep. When the bubble reaches the surface, its volume is 6cm3. What
was the volume of the air bubble at the bottom of the lake?&lt;/p&gt;
&lt;p&gt;&amp;nbsp;&lt;/p&gt;
&lt;p&gt;How do you solve this question?&lt;/p&gt;
&lt;p&gt;&amp;nbsp;&lt;/p&gt;
&lt;p&gt;&amp;nbsp;&lt;/p&gt;</description>
      <pubDate>Sat, 19 Jul 2008 22:04:54 +0800</pubDate>
      <guid isPermaLink="false">politics.sgforums.com:2297:324678:8253282</guid>
      <author>bonkysleuth</author>
      <link>http://politics.sgforums.com/forums/2297/topics/324678</link>
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