Originally posted by charlize:
Using a simple 2x2 Nash equilibrium model in this case is an over simplification of a political matter which has too many variables.
If I understand the example correctly, you are implying that the government should allow the opposition to "win" seats in Parliament by not contesting the wards the opposition are contesting in for Singapore to have a win-win situation.
So how many seats exactly does the ruling party "give" to the opposition?
1 seat? 10 seats? Or until it is 51%-49% in favour of the ruling party?
I don't think Nash Equlibirium can be meaningfully applied in this situation, since it is not just a matter of win-win situation. There are also political implications to consider.
Agree...there are some problems with this model as well. It presupposes plans of action that have not been carried out. Nash Equilibrium is based on the assumption that two or more actors should not deviate from their strategy, so as to gain optimal payoffs.
The strategies for both opposition and ruling party are different: The PAP would wish to fully dominate parliament (i.e. no opposition), while the opposition has to increase or at least maintain its current representation in parliament. As is, the odds are already heavily stacked against them.
Taking your assumption that the Yes/No represents decision, the outcome for PAP = Yes, and Opposition = No, the outcome will still invariably lead to stronger PAP dominance, notwithstanding what little the opposition can actually do about it. (I refer to the top right box)
A policy of no-contest would mean that the status quo remains. This remains questionable...Potong Pasir remains under opposition, but just barely...
Perhaps what we need to employ in place of this is a series of mixed game strategies...
Nash Equilibrium...sometimes referred to as Prisoner's Dilemma, is not feasible in this case, since the results would still favour the dominant group. Further, the chances that one side would 'defect' are very high in this instance.
My 2 cents..
