//------Zee 51 Ouis for my kantang crapbox------//

• sammiegal

  31 May 06, 01:39

  Originally posted by hisoka:

  erm okz i get a bad feeling that i will be on your mind often whern you play badminton
  
  i dunno how to play tennis, who wanna teach me?
  
  sammie, you can post the question here and lets see if the 2 students here can help

  determine the largest possible domain of each of the following functions.
  
  f: x -> 6x+7 / 2x+3
  
  i just learned functions.. and i havent realli been paying attention.. sighs.
• hisoka

  31 May 06, 01:39

  Originally posted by starblue:

  i also cannot play tennis well lah.. just whack loh. but me whack until very zun leh... my PE teacher last time wanna jio me to join tennis.

  aim at the player arh?
  
  or aim at the referee?
  
  i sometime wonder what happenesif some teniss player misaim and send the ball or the racket flying at the referee
• LazerLordz

  31 May 06, 01:40

  Originally posted by starblue:

  u for wad??

  dashed hopes of an invititation.
• hisoka

  31 May 06, 01:41

  Originally posted by sammiegal:

  determine the largest possible domain of each of the following functions.
  
  f: x -> 6x+7 / 2x+3
  
  i just learned functions.. and i havent realli been paying attention.. sighs.

  ask you har domain is the values x can take or the values f(x) can take?
  
  if its x then the answer should be x != -3/2 bah
• LazerLordz

  31 May 06, 01:43

  I have to confess that Bleu's CAP makes me feel miserable..
• sammiegal

  31 May 06, 01:43

  Originally posted by hisoka:

  ask you har domain is the values x can take or the values f(x) can take?
  
  if its x then the answer should be x != -3/2 bah

  the answer is that la.. but i needa know how to do the working!!
• sammiegal

  31 May 06, 01:44

  Originally posted by LazerLordz:

  I have to confess that Bleu's CAP makes me feel miserable..

  creative arts portfolio? o.O
• starblue

  31 May 06, 01:44

  Originally posted by hisoka:

  ask you har domain is the values x can take or the values f(x) can take?
  
  if its x then the answer should be x != -3/2 bah

  yup. this one is easy...
  
  the denominator cannot be zero. so u take the denominator and equate it to zero. find the value of x for which that equation is satisfied. that would be the answer.
  
  so your denominator is 2x +3 = 0. solve for x.
• Simple_Bear

  31 May 06, 01:45

  Originally posted by starblue:

  /kicks bear out of SH

  *grabs Starblue's leg...
  
  Gal cannot be tt chor lor...
  
  
• starblue

  31 May 06, 01:45

  Originally posted by hisoka:

  aim at the player arh?
  
  or aim at the referee?
  
  i sometime wonder what happenesif some teniss player misaim and send the ball or the racket flying at the referee

  of cos is aim at the court where the player cannot hit back lah... maybe its cos my opponents suck at it more than i do.
• LazerLordz

  31 May 06, 01:45

  Originally posted by sammiegal:

  creative arts portfolio? o.O

  Cumulative Average Point. or something like that.. grade averages.
  
  
• starblue

  31 May 06, 01:46

  Originally posted by LazerLordz:

  I have to confess that Bleu's CAP makes me feel miserable..

  o.O why suddenly talk about CAP again?
• hisoka

  31 May 06, 01:46

  Originally posted by sammiegal:

  the answer is that la.. but i needa know how to do the working!!

  hmmz okz basically domain refers the values that x can take that satisfy the function f.
  
  so in this case, the only value that x cannot take would be when x = -3/2 where the denominator is zero and therefore making f undefined
  
  i not sure if theres a proper way to find the undefined values though. but definitely values when the denominator = 0 unless there is a common factor with the numerator
• starblue

  31 May 06, 01:47

  Originally posted by Simple_Bear:

  *grabs Starblue's leg...
  
  Gal cannot be tt chor lor...
  
  

  ni guan wo??
  
  /steps on bear's toes with stiletto.
• hisoka

  31 May 06, 01:48

  Originally posted by starblue:

  ni guan wo??
  
  /steps on bear's toes with stiletto.

  is starblue wearing skirt?
  
  bi think cap is cumulative average points. anyway yeah lor why suddenly bring in such a sad topic
• LazerLordz

  31 May 06, 01:48

  Originally posted by starblue:

  o.O why suddenly talk about CAP again?

  saw the thread about blessings.
• starblue

  31 May 06, 01:49

  Originally posted by hisoka:

  hmmz okz basically domain refers the values that x can take that satisfy the function f.
  
  so in this case, the only value that x cannot take would be when x = -3/2 where the denominator is zero and therefore making f undefined
  
  i not sure if theres a proper way to find the undefined values though. but definitely values when the denominator = 0 unless there is a common factor with the numerator

  yup yup...
  
  if your function is in square root. then wadever is in the square root cannot be negative. u just take that expression in x and make it smaller or equal to zero and solve for x. that will be your answer.
  
  the principle is this: if your x is that particular value, then wadever is in the square root (or denominator) will be negative (or zero), and u cant define square root of a negative number (or a fraction with zero denominator).
  
  understand?
• starblue

  31 May 06, 01:50

  Originally posted by LazerLordz:

  saw the thread about blessings.

  oh.. wad is your cap??
• sammiegal

  31 May 06, 01:51

  Originally posted by hisoka:

  hmmz okz basically domain refers the values that x can take that satisfy the function f.
  
  so in this case, the only value that x cannot take would be when x = -3/2 where the denominator is zero and therefore making f undefined
  
  i not sure if theres a proper way to find the undefined values though. but definitely values when the denominator = 0 unless there is a common factor with the numerator

  hmm okay i get it.. somewhat. but erm. this question leh? same instructions.
  
  square root (x square plus 2)
• hisoka

  31 May 06, 01:51

  Originally posted by starblue:

  yup yup...
  
  if your function is in square root. then wadever is in the square root cannot be negative. u just take that expression in x and make it smaller or equal to zero and solve for x. that will be your answer.
  
  the principle is this: if your x is that particular value, then wadever is in the square root (or denominator) will be negative (or zero), and u cant define square root of a negative number (or a fraction with zero denominator).
  
  understand?

  actually you can define square root of a negative number.,, thats complex numbers. i think its still valid since they never define that f(x) must be real
• starblue

  31 May 06, 01:52

  Originally posted by hisoka:

  actually you can define square root of a negative number.,, thats complex numbers. i think its still valid since they never define that f(x) must be real

  -_-" for a maths u dun learn complex numbers... u must teach them according to their standard.
• starblue

  31 May 06, 01:53

  Originally posted by sammiegal:

  hmm okay i get it.. somewhat. but erm. this question leh? same instructions.
  
  square root (x square plus 2)

  oei oei oei.. i told u le.... i knew this quesiton will come up one.. go read the instructions and try the question yourself...
• hisoka

  31 May 06, 01:54

  Originally posted by sammiegal:

  hmm okay i get it.. somewhat. but erm. this question leh? same instructions.
  
  square root (x square plus 2)

  erm i would say -infinity < x < infinity
  
  but then i think the answer is as starblue says. to let the term in square roots to be smaller than zero and solve
• hisoka

  31 May 06, 01:55

  Originally posted by starblue:

  -_-" for a maths u dun learn complex numbers... u must teach them according to their standard.

  hmmz i thought i remember A maths got abit of complex number one leh
• sammiegal

  31 May 06, 01:56

  Originally posted by hisoka:

  erm i would say -infinity < x < infinity
  
  but then i think the answer is as starblue says. to let the term in square roots to be smaller than zero and solve

  im reading the instructions!! so whatever equation that's in the square root thing should be made equal to zero or less then that. but the answer given is weird.. do i equate it to anithing??