a)Originally posted by lavastar:find dy/dx if
a) f'(x) = sq root (X^2 - 1) and y=f(x^2)
b) f'(x) = cos(x^2) and y = f(2x divided by x+1)
[Note: f'(x) means differentiating f(x) 1 time]
Is it that this problem can only be solved by integration? cause i have not learned integration in h2 maths yet..
Any help please?![]()
wow thats fast.. thank u..Originally posted by eagle:a)
so dy/dx = f'(x^2) * 2x using chain rule
b)
similar to a). You should be able to do now