Originally posted by wishboy:
A thermocouple is set up with the cold junction placed in melting ice at 0°C.
When the hot junction is placed in boiling water, the e.m.f. measured is 12.00 mV.
When the hot junction is placed in liquid with temperature è, the e.m.f. measured is 4.20 mV.
What is the temperature of the liquid?
i know about the general equation, è=(x_è-x_0)/(x_100-x_0 )
but dunno substitute which value into which
EDIT: sec 3 lvl here
I can't rmb whether emf measured by the thermocouple is directly proportional to the difference of temperature between the cold junction and the hot junction.
If it is,
E = ad
where E is the emf, a is a constant and d is the difference in temperature between the cold junction and hot junction.
When E = 12 mV, d = 100 - 0 = 100,
12 = a(100)
a = 0.12
E = 0.12 d
When E = 4.20,
4.20 = 0.12 d
d = 35
Therefore, temperature of the liquid = d + 0
= 35