Originally posted by dbowie:
Mg + H2SO4 -> MgSO4 + 2H
This is fundamentalLy wrong.
Firstly, according to the law of conservation of charge, there's no way that u can have 2H+ surviving on the right hand side while the left hand side has no total charge of +2.
Secondly, the only possible way for 2H to exist is when the whole reaction is done in gaseous state at high temperatures (ie the hydrogen is atomised), else it is almost impossible for hydrogen to exist as monoatoms. They preferentially exist as H2 at room temperature and pressure.
Thirdly, if this is an ionic equation in aqueous medium, the equation is wrong. It should be Mg(s) + 2H+ (aq) -> Mg2+ (aq) + H2 (g) as (SO4)2- is a spectator ion since magnesium sulphate is soluble and remains in solution with no chance in state.
Hence my only logical conclusion is that the above equation is wrong. For O/A levels, the correct equation should be Mg + H2SO4 -> MgSO4 + H2 and NEVER write H2 gas as 2H. Perhaps it was copied wrongly or a printing error.
As such, may I ask where is the source of this equation so that I could perhaps reach a better conclusion?
*EDIT*
To add on, for a metal + acid reaction, hydrogen gas is
ALWAYS released and it
DOES NOT remain in the solution as H+ ions.
Of course some may argue that H2 gas may exist in an equilibrium with H+ ions in the presence of water but that is
STRICTLY OUT OF TOPIC AND DON'T BOTHER ABOUT IT FOR O/A LEVELS. *ENDS EDIT*
Thanks and cheers for your mugging!
