Very simple emaths qn

• wishboy

  29 Sep 07, 14:43

  Simplify the following, giving ur ans in positive indices
  
  (1-x) / [1-x^(1/2)]
  
  i suddenly forget how to do
• polarsnake

  29 Sep 07, 15:34

  Damn.... I lost touch on my maths le
• HyuugaNeji

  29 Sep 07, 15:39

  Originally posted by wishboy:

  Simplify the following, giving ur ans in positive indices
  
  (1-x) / [1-x^(1/2)]
  
  i suddenly forget how to do

  (1-x) / [1-x^(1/2)] * [(1+x^(1/2))/(1+x^(1/2))]
  =(1-x)[(1+x^(1/2))/[1-x]
  =1+x^(1/2)
  
  using the identity a^2-b^2=(a-b)(a+b)
• wishboy

  29 Sep 07, 15:50

  thanks
• eagle

  29 Sep 07, 15:57

  Originally posted by HyuugaNeji:

  (1-x) / [1-x^(1/2)] * [(1+x^(1/2))/(1+x^(1/2))]
  =(1-x)[(1+x^(1/2))/[1-x]
  =1+x^(1/2)
  
  using the identity a^2-b^2=(a-b)(a+b)

  Or you can separate the top to
  
  (1+x^(1/2))/(1-x^(1/2))
  
  
• ^tamago^

  29 Sep 07, 16:06

  1+x^½