E MATH
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16b) (-4 3)
21ai) 5/16 ii)5/16 iii)3/8 b)55/128 -
15b. Since it is "similar in shape", the proportion of length to width to height is the same. Thus,
$1.20 × (2)³ = $9.60
16a. since ABCD is a //gram, vector AB = vector DC
|BE|
= (2/3) |BC|
= (2/3) |AC-AB|
= (2/3) |AD+DC-AB|
= (2/3) |AD| (since AB=DC)
= (2/3) |(3,-4)|
= (2/3) sqrt(9+16)
= (2/3) sqrt(25)
= 10/3
16b. let vector FE = k vector FA
k
= |CE|/|AD|
= |BC/3|/|BC| (since BC=3CE and AD=BC)
= 1/3
vector AE
= vectors AD+DC+CE
= vectors AD+AB+(CB/3)
= 2/3 AD + AB (since CB = -AD)
= 2/3 (3,-4) + (6,2)
= (8,-2/3)
FE = FA/3 = (1/3)(FE+EA)
(2/3)FE
= (1/3)EA
= (-1/3)AE
FE
= (-1/2)AE
= (-1/2)(8,-2/3)
= (-4,1/3)
21. Total number of outcomes = 2×2×2×2=16
ai. [P(H,T,T,T)+P(T,H,T,T)+P(T,T,H,T)+P(T,T,T,H)+P(T,T,T,T)]/total number of outcomes = 5/16
aii. [P(H,H,T,T)+P(H,T,H,T)+P(H,T,T,H)+P(T,H,H,T)+P(T,H,T,H)+P(T,T,H,H)]/total number of outcomes = 3/8
aii. [P(T,H,H,H)+P(H,T,H,H,)+P(H,H,T,H)+P(H,H,H,T)+P(H,H,H,H)]/total number of outcomes = 5/16
b. P(win,lose)+P(lose,win)
= (5/16)×[1-(5/16)]+[1-(5/16)]×(5/16)
= (5/16×11/16)+(5/16×11/16)
= 55/256 + 55/256
= 55/128 -
so its volume hor...o ya...hmmz! damn.Originally posted by ^tamago^:15b. Since it is "similar in shape", the proportion of length to width to height is the same. Thus,
$1.20 × (2)³ = $9.60 -
omgs 21 so chim
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frankly my format may not be right cos i'm more of an A Maths person, adjust to relevant format.
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21 Just draw your tree diagram la
4 columns for 4 coins
Each coin has a head or tail, leading to the other column -
u draw and let me see o.oOriginally posted by lpx88:21 Just draw your tree diagram la
4 columns for 4 coins
Each coin has a head or tail, leading to the other column
cuz i dunno how to draw lols iget 5/8 not 5/16 for the first ans -
btw how do we do questions such as HCF,LCF, LCM, HCM.???
Smth like
number 45 written as product of its prime factors is 45 = 3 x 3 x5 -
should be very easy bah.Originally posted by Y_Shun:btw how do we do questions such as HCF,LCF, LCM, HCM.???
Smth like
number 45 written as product of its prime factors is 45 = 3 x 3 x5
For 2 numbers a and b, the HCF × LCM = a × b. But I don't think this was ever tested.