Debrief -> Pure Physics
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Discuss here
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overally easy, minused about 10+/- marks. hope paper 1 can score well
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way easier than my prelim. But made a few easy careless mistakes though.
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manageable paper for a physics noob like me Yaays can get B liao
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flunk my first qns..like 7 marks gone already....just from first qns...
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the stupid qn about the variable resistor and the 2 voltmeters, i anyhow put. zzz
other than that i find it easy lah. 1 week ++ and Os are OVER -
Don't think about O's endding and flunk the rest of the papers. At least that what happened to me last time. In the end did badly for a few papers.
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Should be studying lor, you all. Shoo!
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Voltmeter 1 is dec then i go change to incr..zzz...Originally posted by thehappybunny:the stupid qn about the variable resistor and the 2 voltmeters, i anyhow put. zzz
other than that i find it easy lah. 1 week ++ and Os are OVER
Voltmeter 2 inc
Ammeter dec
I was stuck at that for at least 10 mins -
anyone managed to do the average frictional force on the rocky road one?
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Use F=ma. a is givenOriginally posted by eagle:anyone managed to do the average frictional force on the rocky road one? -
from what I understand from the question, seems like if u use F=ma, it is wrong because the final frictional force calculated will include the gravitational forceOriginally posted by rain-coat:Use F=ma. a is given
The car went up a slope right? -
K.E gained at 1st minus G.P.E gained at the endOriginally posted by eagle:anyone managed to do the average frictional force on the rocky road one?
Then use that value, divide over the distance 40m to get the frictional force per metre?
Rationale is by right K.E should be totally converted to G.P.E?
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correctOriginally posted by lpx88:K.E gained at 1st minus G.P.E gained at the end
Then use that value, divide over the distance 40m to get the frictional force per metre?
Rationale is by right K.E should be totally converted to G.P.E?
that was what I explained to my sis
That is due to conservation of energy
Initial KE = Final GPE + Work Done against friction -
tt friction qns..use 560kJ - gpe of car to get frictional force right?
den divide by distance to get avg frictional force...
i minus about 20 marks for p2 le...zzz my a1.... -
How about the question about tube of the pressure when the volume is 1200cm^3?
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Boyle's law?Originally posted by zhou_qiang:How about the question about tube of the pressure when the volume is 1200cm^3?
P1V1=P2V2 -
minus already is get work done by frictional forceOriginally posted by absol:tt friction qns..use 560kJ - gpe of car to get frictional force right?
den divide by distance to get avg frictional force...
i minus about 20 marks for p2 le...zzz my a1....
divide by distance get av frictional force
ur method is correct, but phrasing is wrong -
Question 1.
Describe the motion of the car. -
When the car moves, it goes from point A to point B....Originally posted by zhou_qiang:Question 1.
Describe the motion of the car.
discuss the Bio paper tomorrow more beneficial.... -
Oops sorry