Debrief - 9740 Mathematics
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At least I can afford to have a small smile this time
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this h2 math ah?
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I found myself whining even though I lost about 2 marks.
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i lost like 16 marks..
dun think can get a liao.. -
mi o level nia
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how you all find the paper? post all the answers lehz~
<50 50 >50 which category are you in?
you either do very well or tio owned
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TMD tio owned ....my own fault...never study...i did soooooooo badly that i'll fail...Anyone knows if i can retake only math next year, then use the second year's result combine wth this year de result? My other subjects still ok...
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How can ?Originally posted by dragoncloud:TMD tio owned ....my own fault...never study...i did soooooooo badly that i'll fail...Anyone knows if i can retake only math next year, then use the second year's result combine wth this year de result? My other subjects still ok... 
I think the last 2-3 questions were really a bummer. -
i 10 marks gone le.. nv do the other complex numbers question, not the Argand diagram one.
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my ques 7 and 8 are so horrible.
10 last part didnt do
11 last part is something that i sub and sub till whole page was in a mess
damn. how to get A? -
how many qns were there altogether? why some pplz sae got 11 some say got 12?
question 1 got 2 answers correct notz?? -
did anyone manage to prove the ans for the last ques area of triangle: the (1/12) (sin theta) (blah blah bah)...
and the last part which was 2 integrate ( cos t)^3 (sin t) ? dam sht man. i got -2 integrate ( cos t) ^3 (sin t) instead. -
i can prove the area of triangleOriginally posted by dxdx:did anyone manage to prove the ans for the last ques area of triangle: the (1/12) (sin theta) (blah blah bah)...
and the last part which was 2 integrate ( cos t)^3 (sin t) ? dam sht man. i got -2 integrate ( cos t) ^3 (sin t) instead.
but not the integration one -
11 questionsOriginally posted by th3m0ment:how many qns were there altogether? why some pplz sae got 11 some say got 12?
question 1 got 2 answers correct notz??
ques 1 ya got 2 answers. 1-6 is easy btw. nightmare starts at 7
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what is with qn 9? got pplz noe how to do nortz?
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7 also is complex no. Was dam turned of once I turn to the last 2 pages! Especially the last question.Originally posted by striderz_o405:11 questions
ques 1 ya got 2 answers. 1-6 is easy btw. nightmare starts at 7 -
converging diverging ?Originally posted by th3m0ment:what is with qn 9? got pplz noe how to do nortz?
i know what it means, but then my explanation a lil suck though
estimated 4 marks gone -
i din noe how to do 9. what is your answer?
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somehow i just play around with the calc and all the values seem to be moving towards 0.619 for numbers below 1.512Originally posted by th3m0ment:i din noe how to do 9. what is your answer? -
Wah you long term memory, the numbers remember until so exact.Originally posted by striderz_o405:somehow i just play around with the calc and all the values seem to be moving towards 0.619 for numbers below 1.512
My friend tell me plot graph for that question. How did you play around with the calculator? That's the question I didn't know how to do in the paper. Horrorrr. Question 9 (iii) and (v). They are linked, so too bad for me =/ I know how to do (iv) though.
Then I also spotted a careless mistake after the paper.
Question 11, the sketching of the graph. I went to draw both the graph below and above the x-axis when you're only required to draw the one above. Sigh =/ -
Ok now let me recall all the various questions...Originally posted by tangjing:Wah you long term memory, the numbers remember until so exact.
My friend tell me plot graph for that question. How did you play around with the calculator? That's the question I didn't know how to do in the paper. Horrorrr. Question 9 (iii) and (v). They are linked, so too bad for me =/ I know how to do (iv) though.
Then I also spotted a careless mistake after the paper.
Question 11, the sketching of the graph. I went to draw both the graph below and above the x-axis when you're only required to draw the one above. Sigh =/
Qn 11)
I got the graph wrong by including the bottom part too. 1 mark gone. Anyway for the 2nd part, it is possible to show the expression although the step is tedious (I did and cancelled my original answer twice. Did in pencil on the qn paper before copying the solution onto my paper later on). Integration one was rather easy. Just need to eliminate the cos t term by multiplying by dt/du which is 1/cos t.
Qn 10)
I believe the majority were asking about the values for n which S > 4a. Ok at first, u have to find ur d in terms of a. Use ur ar - a = 3d to get the result that d = -1/9 a. Then sub this expression back into the inequality. You will get a quadratic inequality of something like an^2 - 19an + 72a < 0. You can divide by a as a > 0 as defined by the question. Therefore u get n^2 - 19n + 72<0. Solve for n which should be in the range of (5+,13+), therefore n should be 6 to 13 as n is an integer.
Qn 9)
2nd part: When X1=0, X will increase towards alpha. X1 = 1, X will decrease towards alpha. X1 = 2, X will increase to infinity.
3rd part: Proving that X(n+1)>Xn for Xn between values of alpha and beta. To prove it, first express X(n+1)-Xn = 1/3 * e^(Xn) - Xn. Let Xn be x, therefore expression will give you 1/3 of the equation of the graph (e^x - 3x). When Xn is between alpha and beta, e^x - 3x is always less than zero. Since 1/3 * anything negative is less than zero, therefore X(n+1) - Xn < 0, X(n+1) < Xn. You can prove the other case using this method too.
That's all for qn 9, 10 and 11.
*EDIT* Range of values for n should be 6 to 13, not 5 to 13. Sorry if I made anyone panic. -
*clap clap*Originally posted by teraexa:Ok now let me recall all the various questions...
Qn 11)
I got the graph wrong by including the bottom part too. 1 mark gone. Anyway for the 2nd part, it is possible to show the expression although the step is tedious (I did and cancelled my original answer twice. Did in pencil on the qn paper before copying the solution onto my paper later on). Integration one was rather easy. Just need to eliminate the cos t term by multiplying by dt/du which is 1/cos t.
Qn 10)
I believe the majority were asking about the values for n which S > 4a. Ok at first, u have to find ur d in terms of a. Use ur ar - a = 3d to get the result that d = -1/9 a. Then sub this expression back into the inequality. You will get a quadratic inequality of something like an^2 - 19an + 72a < 0. You can divide by a as a > 0 as defined by the question. Therefore u get n^2 - 19n + 72<0. Solve for n which should be in the range of (5+,13+), therefore n should be 5 to 13 as n is an integer.
Qn 9)
2nd part: When X1=0, X will increase towards alpha. X1 = 1, X will decrease towards alpha. X1 = 2, X will increase to infinity.
3rd part: Proving that X(n+1)>Xn for Xn between values of alpha and beta. To prove it, first express X(n+1)-Xn = 1/3 * e^(Xn) - Xn. Let Xn be x, therefore expression will give you 1/3 of the equation of the graph (e^x - 3x). When Xn is between alpha and beta, e^x - 3x is always less than zero. Since 1/3 * anything negative is less than zero, therefore X(n+1) - Xn < 0, X(n+1) < Xn. You can prove the other case using this method too.
That's all for qn 9, 10 and 11. -
can post the answers for qn 1-8 also?
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Yo guys
I am still enjoying my post promos holidays -
standard. In O level, they are supposed to put the questions from easiest to hardest. (roughly).Originally posted by RaaRaa:7 also is complex no. Was dam turned of once I turn to the last 2 pages! Especially the last question.
This is so that pple dont give up when they see the first 3 questions. 16 years old still considered young. If you put 3 difficult questions in front, young students will panic and screw up whole paper.