Integrate problem
-
Eh how do u integrate f ( x- 0.5) e^-2x dx ?
-
why is there an "f" there?Originally posted by Isis:Eh how do u integrate f ( x- 0.5) e^-2x dx ?
try by parts? i havent tried it myself though
-
The formula isn't in my notes ..
the notes that have this formula has been discarded...... -
why is there an "f" there?Originally posted by Isis:Eh how do u integrate f ( x- 0.5) e^-2x dx ?
try by parts? i havent tried it myself though
f is the integrate curvy line thingy.. -
Let f = integral symbol.Originally posted by Isis:Eh how do u integrate f ( x- 0.5) e^-2x dx ?
f((x- 1/2)e^-2x)dx
Break it up
Let u = x-1/2
let du=x-1/2 dx
let dw =e^-2x
let w= -2e^2x
So basically fu dw= uw-fwdu (got it on paper but difficult to transfer)
=f((x- 1/2)e^-2x)dx
= (x-1/2)(-2e^2x)- f(-2e^2x)(x-1/2 dx)
= (few more steps same as the uw-fwdu)
= -1/2(e^(2x))x
Law of exponential integrals
fe^x dx = e^x +C
Not sure if I got right then again ...I got no A levels....so you have to give way . -
The answer is -0.5xe^-2x + c, using integration by parts.