Physics D01/P2/Q6b(ii) (Static Electricity)
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The figure shows the charge distribution on the 2 drops when they are in the electric field between the cloud & the ground. Drop 1 moves upwards & briefly touches drop 2.
(i) Explain what happens to the charges on the 2 drops as they touch.
(ii) Having touched, the drops now separate. State what charges will now be found on drop 1 & on drop 2.
My solution to (ii) is: When drop 1 & drop 2 touch, the charges on drop 1 (-ve charge) & drop 2 (+ve charge) will neutralise each other. Then drop 1 will be +vely charged & drop 2 -vely charged. Ultimateli the 2 droplets will be neutral when they separate since drop 1 (+ve) will neutralise drop 2 (-ve). Is it correct to sae dat?
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Your question is very vague. So is drop 1 +ve or -ve?
And is drop 2 +ve or -ve?
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Having touched, the drops now separate. State what charges will now be found on drop 1 & on drop 2.
Is that the full question? The "having touched" part did not really made sense to me.
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When they separate, drop 2 should be -ve and drop 1 should be +ve.
That's assuming both drop 1 and 2 are conductors... I will draw out a diagram and post it out tonight.