(see below)
Is there anything wrong? My answer is different from the answer key!

Originally posted by secretliker:
Same answer if you change the denominator to sin^2, but rather inefficient. Why not do it in just 2 lines?
I hv added a link to the above post.
Originally posted by secretliker:(see below)
Is there anything wrong? My answer is different from the answer key!
what is the answer key... trigo functions can be expressed differently....
may I know which level you are at?
1 / (1 - cos x)
I'm helping my brother who's in Sec 4.
Originally posted by secretliker:1 / (1 - cos x)
I'm helping my brother who's in Sec 4.
u can simply
-(1+cos x) / (1-cos^2 x)
- (1+cos x) / [(1+cosx)(1-cos x)]
- 1 / (1 - cos x)
Do check if the minus sign is there
Thanks eagle! I overlooked the a^2 - b^2 = (a+b)(a-b) thing. No wonder I can't get it.
Yes, there's minus sign.
gosh eagle is godly~.
a round of applause~~...
i only thinking how to solve when he can get it all right.
nah... I think I will forget most stuff in a few years time
So now while I still remember some, I try to help whenever possible...
Originally posted by hiphop2009:i only thinking how to solve when he can get it all right.
only needs 2 steps to solve...