All aminos acid are polar right ? since alpha carbon is singly bonded to 4 diff groups of atoms
including glycine too, which has 2 H atoms bonded to alpha carbon
please kindly check page 36 of this thread where i uploaded my drawing of proline !
Originally posted by Flying grenade:ultima can help check if i circle the correct R (in this case the alkyl ) group correctly, in my sketch of Proline, please !
https://www.dropbox.com/s/73pbse5uds7ib0j/20160705_181640-1.jpg?dl=0
Thank u !
Originally posted by Flying grenade:All aminos acid are polar right ? since alpha carbon is singly bonded to 4 diff groups of atoms
including glycine too, which has 2 H atoms bonded to alpha carbon
please kindly check page 36 of this thread where i uploaded my drawing of proline !
All of these species (including the zwitterion) is even more 'polar' than a 'polar molecule' (the term implies overall neutral, and usually with no formal charges present), due to formal charges present and (other than the zwitterion) hence also ionic charges present.
Originally posted by UltimaOnline:
More or less correct. But you may be penalized by Cambridge, because your circle (can be distorted circle, doesn't have to be perfectly circular) includes the alpha C atom, which is not part of the R group.
Noted, thank you so much! won't circle the alpha C atom in the future !
Thank you, Ultima !!!
[Not very important]
page 81 cs toh advanced guide
he said pH2O can be obtained from the Data booklet (given as a function of temp)
how to calculate it?
tried to figure out myself for some time but couldn't figure out. tried to research online and use the data booklet and use ideal gas eqn but to no avail.
from the internet, can obtain vapor pressure of(pure) H2O to be 3.17kpa (to 3sf) , at 25°C, consistent with example 3 of cs toh advanced guide page 81
Not sure how to calculate pH2O(g) as a function of temperature from data booklet as suggested by cs toh,
but it can be calculated by this method(not very simple, but manageable) :
peruse this
https://en.m.wikipedia.org/wiki/Vapour_pressure_of_water
and this
https://en.m.wikipedia.org/wiki/Antoine_equation
page 82 cstoh advanced guide, btm of page , elicited my thought on this :
my sch taught me this (when drawing structures )
double bond more favourable to form compared to single bond,
if can form covalent single bonds, it's preferable/more likely to form compared to dative bond
electronegative atom unlikely to donate lp of e- to form dative bond ( donate dative bond )
is this a good guideline?
what is the name of the reaction that causes displacement of the salt? Displacement reaction? Re-precipitation reaction?
for e.g. , SO42- + BaCl2 -> BaSO4 + 2Cl-
Originally posted by Flying grenade:what is the name of the reaction that causes displacement of the salt? Displacement reaction? Re-precipitation reaction?
for e.g. , SO42- + BaCl2 -> BaSO4 + 2Cl-
No comments regarding your other posts. To one, irrelevant to A level syllabus, don't waste your time. If you're itching to do some calculation involving water, calculating the pKa of H2O (at 25 degrees Celsius) is more relevant to the syllabus. Try calculating it out yourself before you google the answer. (Hint : you'll first need to calculate the molarity of pure water, before you can calculate the pKa of water).
To the other, you need to hands-on practice drawing and test yourself on as many different (and unusual) structures as possible, to test out for yourself your school guidelines to see if they're useful for yourself or not.
As practice (all you JC students, school teachers and private tutors reading this), try drawing out the full displayed structural formula for the following species, showing all lone pairs, bond pairs, formal charges, oxidation states, and dative bonds (if any), for the following structures. Challenge yourself to draw them out yourself first, before you google out the answer to check.
ClO
ClO2
Cl2O
Br2O3
Br2O4
Br2O5
Cl2O6
Cl2O7
S2O4 2-
S2O5 2-
S2O6 2-
H4P2O7
H5P3O10
KHF2
[ClF6]+
[AsF6]-
[XeF]+
[SbF6]-
[XeO2F]+
[XeOF3]+
[C6F5Xe]+
[(C6F5)2BF2]-
HN3 (not NH3)
[N5]+
IH5O6
[H2I2O10] 4-
[I2O9] 4-
((Methyl)2SiO3)3
C3H3N3O3
P4O6
P4O7
P4O10
P4O6S4
[P3O9] 3-
[P3O10] 5-
[P4O12] 4-
[SiO4] 4-
[Si2O7] 6-
[Si6O18] 12-
B4Cl4
B9Cl9
B2H6
B4H10
B5H9
B5H11
[B6H6] 2-
[B12H12] 2-
[B2(O2)2(OH)4] 2-
[B5O6(OH)4]-
[B4O5(OH)4] 2-
OMG THANKKK YOUU SO MUCH ULTIMAAA!!! especially the list of molecules Thanks
Originally posted by Flying grenade:OMG THANKKK YOUU SO MUCH ULTIMAAA!!! especially the list of molecules Thanks
Btw, you'll first need to calculate the molarity of pure water, before you can calculate the pKa of water at 25 degrees Celsius.
what does 'FA' abbreviation stand for in titration solutions e.g. FA1 and FA2?
always wanted to know abt this but couldn't find out
searched internet and legit cant find anything FA related to chemistry ,
My guess is Formal Analyte
xD
Originally posted by Flying grenade:what does 'FA' abbreviation stand for in titration solutions e.g. FA1 and FA2?
always wanted to know abt this but couldn't find out
searched internet and legit cant find anything FA related to chemistry ,
My guess is Formal Analyte
xD
why polymer, then cannot have geometric (cis-trans) isomerism? there's double bond within polymer
Originally posted by Flying grenade:why polymer, then cannot have geometric (cis-trans) isomerism? there's double bond within polymer
THANKSS ULTIMAA !! thanks for all the knowledge
page261 cstoh advanced guide d orbital splitting
page 222 2nd print George chong inorganic chem book d orbital splitting
page 450 K.S. Chan physical inorganic chem book
george chong's and K.S. Chan's book show energy of d* orbitals are of higher energy than ground state 3d orbitals, in a free metal ion
cstoh's book shows the splitting causes some orbitals to be of less and more energy compared to 3d isolated orbitals
Originally posted by Flying grenade:page261 cstoh advanced guide d orbital splitting
page 222 2nd print George chong inorganic chem book d orbital splitting
page 450 K.S. Chan physical inorganic chem book
george chong's and K.S. Chan's book show energy of d* orbitals are of higher energy than ground state 3d orbitals, in a free metal ion
cstoh's book shows the splitting causes some orbitals to be of less and more energy compared to 3d isolated orbitals
http://www.chemguide.co.uk/inorganic/complexions/colour.html
https://en.wikipedia.org/wiki/Crystal_field_theory#Crystal_field_stabilization_energy
OMMMMMMMMGGGGGGGGGGG THANKSSS ULTIMAAAA
u are godly
version of chemguide and wiki is indeed better for this case
Hi, I have a question for chemistry and read you can post them here?
5.00g of an anhydrous Grp 2 metal nitrate loses 3.29g in mass when heated strongly
2M(NO3)2 => 2MO+4NO2+O2
What is metal M?
Magnesium
Calcium
strongtium
barium
Originally posted by Molestermannn69:Hi, I have a question for chemistry and read you can post them here?
5.00g of an anhydrous Grp 2 metal nitrate loses 3.29g in mass when heated strongly
2M(NO3)2 => 2MO+4NO2+O2
What is metal M?
Magnesium
Calcium
strongtium
barium
cs toh didnt notice this ,or at least he didn't update this
pg 188 chem advanced guide
the 'slow' and 'fast' is wrong, and must be cancelled right?
Originally posted by Flying grenade:cs toh didnt notice this ,or at least he didn't update this
pg 188 chem advanced guide
the 'slow' and 'fast' is wrong, and must be cancelled right?
Originally posted by UltimaOnline :
I'll leave it to Flying Grenade (don't disappoint me) to show you how to solve it.
5.00g of an anhydrous Grp 2 metal nitrate loses 3.29g in mass when heated strongly
2M(NO3)2 (s) => 2MO(s) + 4NO2(g) + O2(g)
What is metal M?
Flying grenade's suggested solution :
Mass MO must be 5.00 - 3.29 = 1.71g
mol = mass/mr
let mr of M be x
ηM(NO3)2 = 5/(x+124)
ηMO=1.71/(x+16)
since stoichiometric ratio of M(NO3)2 to MO is 1:1
we can equate ηM(NO3)2 = ηMO
solving the equations , we obtain x=40.1 (3sf)
Metal M is Calcium.