I less than 3 starblue

• CoolMyth

  18 Apr 05, 23:28

  Just had to say it out....
  
  I don't ask for anything except your permission for me to less than 3 you....
• starblue

  18 Apr 05, 23:29

  wad kok u talking???
• CoolMyth

  18 Apr 05, 23:30

  Originally posted by starblue:

  wad kok u talking???

  I <3 u lah....aiyoh....so paiseh....
• gentlerock

  18 Apr 05, 23:31

  Aiyoh, use PM lah.
• the.raven

  18 Apr 05, 23:31

  prove, for that the limit lim x-> infinity 1/x + 3 = 3 exists
• starblue

  18 Apr 05, 23:31

  Originally posted by CoolMyth:

  I <3 u lah....aiyoh....so paiseh....

  wad you less than 3 me???
• the.raven

  18 Apr 05, 23:31

  Originally posted by starblue:

  wad you less than 3 me???

  
• gentlerock

  18 Apr 05, 23:32

  Originally posted by starblue:

  wad you less than 3 me???

  <3 is a love sign, fallen to one side.
• the.raven

  18 Apr 05, 23:33

  the.raven > all of you add together!!
• starblue

  18 Apr 05, 23:33

  Originally posted by gentlerock:

  <3 is a love sign, fallen to one side.

  right.. now then i know...
• Gwy85

  18 Apr 05, 23:34

  wat u all toking abt? i totally catch no ball!!! Dun tell mi we gt communication breakdown~!
• starblue

  18 Apr 05, 23:35

  Originally posted by Gwy85:

  wat u all toking abt? i totally catch no ball!!! Dun tell mi we gt communication breakdown~!

  at least i'm not the slowest...
• CoolMyth

  18 Apr 05, 23:39

  Originally posted by the.raven:

  prove, for that the limit lim x-> infinity 1/x + 3 = 3 exists

  It suffices to prove that lim (1/x) = 0
  
  Therefore, we have to prove given e > 0, there exist an integer N > 0 such that
  
  x > N --> |(1/x) - 0| < e
  
  Hence, from |(1/x) - 0| < e --> |(1/x)| < e --> x > 1/e.
  
  Choose the smallest integer N such that N _> e, therefore x > N _> 1/e, hence this implies
  
  |(1/x) - 0| < e Therefore lim (1/x) = 0 and hence lim (1/x) + 3 = 3.
  
  Thanks for the impromptu revision.
• phanta5y

  18 Apr 05, 23:40

  lol wtf! less than 3 u hahahahah!!
• starblue

  18 Apr 05, 23:42

  Originally posted by CoolMyth:

  It suffices to prove that lim (1/x) = 0
  
  Therefore, we have to prove given e > 0, there exist an integer N > 0 such that
  
  x > N --> |(1/x) - 0| < e
  
  Hence, from |(1/x) - 0| < e --> |(1/x)| < e --> x > 1/e.
  
  Choose the smallest integer N such that N _> e, therefore x > N _> 1/e, hence this implies
  
  |(1/x) - 0| < e Therefore lim (1/x) = 0 and hence lim (1/x) + 3 = 3.
  
  Thanks for the impromptu revision.

  
  maths is my tian1 di2...
• CoolMyth

  18 Apr 05, 23:42

  Originally posted by starblue:

  right.. now then i know...

  then.....
  
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  what's your reply....?
• meltz

  18 Apr 05, 23:43

  Originally posted by starblue:

  
  maths is my tian1 di2...

  + 1000000000
• the.raven

  18 Apr 05, 23:43

  Originally posted by starblue:

  
  maths is my tian1 di2...

  are you less than 3?
• Gwy85

  18 Apr 05, 23:44

  Originally posted by starblue:

  at least i'm not the slowest...

  ?
  
  eh eh.. u called this "friend" ah? ren shen gong ji.. but mi reali catch no ball
• starblue

  18 Apr 05, 23:44

  Originally posted by the.raven:

  are you less than 3?

  stop making fun of me lah.. i really dunno mah...
• the.raven

  18 Apr 05, 23:45

  Originally posted by meltz:

  + 1000000000

  u all sux, coolMyth is the best
• gentlerock

  18 Apr 05, 23:46

  When's the wedding?
• CoolMyth

  18 Apr 05, 23:54

  Originally posted by gentlerock:

  When's the wedding?

  wedding? I prefer slow and easy....
  
• starblue

  18 Apr 05, 23:55

  Originally posted by CoolMyth:

  wedding? I prefer slow and easy....
  

  bu yao shan zi zuo zu!!
• CoolMyth

  18 Apr 05, 23:59

  Originally posted by starblue:

  bu yao shan zi zuo zu!!

  no, dear(can i call you dear? ), you misunderstood me....
  
  just want to express my heart to you....