Fourier Transform of rect pulse, as pulse get narrow
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top : rect pulse
bottom : it's fourier transform ( representing in frequency domain)
here shown are 3 rectangular pulses and their respective fourier transform
As the width of the rectangular pulse gets narrower, itÂ’s frequency domain expands laterally.
initutively, anyone knows why this happens?
also i heard it has something to do with the Lowest common multiple of the period of the main graph and it's harmonics
can some body please explain to me?
i read the book liao but they never explain in detail
expert please help
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well, the longer the time taken, the lower the frequency.
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longer time of pulse duration u mean?Originally posted by the.raven:well, the longer the time taken, the lower the frequency.
but the lone pulse is not periodic (aperiodic), and hence it shouldnt have any frequency
or rather, frequency = 0 or period = infinity -
lol, ok what I said was wrong, I not expert.Originally posted by HanHao:longer time of pulse duration u mean?
but the lone pulse is not periodic (aperiodic), and hence it shouldnt have any frequency
or rather, frequency = 0 or period = infinity
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go ask the indian prof who is going to teach U part 2.Originally posted by HanHao:top : rect pulse
bottom : it's fourier transform ( representing in frequency domain)
here shown are 3 rectangular pulses and their respective fourier transform
As the width of the rectangular pulse gets narrower, itÂ’s frequency domain expands laterally.
initutively, anyone knows why this happens?
also i heard it has something to do with the Lowest common multiple of the period of the main graph and it's harmonics
can some body please explain to me?
i read the book liao but they never explain in detail
expert please help
he is the expert.
Alas...the power of formal report... 