helpp.. help... if u good in math... plz help....

• torx

  3 Sep 05, 20:10

  6p^2 - 5pq - q^2
  
  how to factorize into (6p+q)(p-q)???
• stellazio

  3 Sep 05, 20:17

  6p\/ q | pq
  p /\ -q | -6pq
  ____________
  6p2 -q2 |-5pq
  
  Oh the 2 V were supposed to be an X indicating the cross..
• dark_snowboy

  3 Sep 05, 20:18

  Originally posted by stellazio:

  6p\/ q | pq
  p /\ -q | -6pq
  _______|_____
  6p2 -q2 | -5pq

  wat u writing
• stellazio

  3 Sep 05, 20:19

  Originally posted by dark_snowboy:

  wat u writing

  Cross method,wrong meh?
• dark_snowboy

  3 Sep 05, 20:20

  Originally posted by stellazio:

  Cross method,wrong meh?

  shit, lost touch, i thought its juz bracket and such
• 798

  3 Sep 05, 20:21

  cross multiply!
  
  another way is perform quadratic equation.
• torx

  3 Sep 05, 20:22

  ohhh... yea!!!!!
  
  i must be really stupid not to see that...
  
  thnks anyway =D
• Xcert

  3 Sep 05, 20:22

  Originally posted by torx:

  6p^2 - 5pq - q^2
  
  how to factorize into (6p+q)(p-q)???

  OK...
  U do cross multiplication...
  1p x 6p =6p^2
  q x -q = -q^2
  1pq-6pq=-5pq
• Martell21

  3 Sep 05, 20:23

  complete the quare!
• hisoka

  3 Sep 05, 20:26

  erm hard to say leh basicsally
  
  6p^2 = 6p*1p
  -q^2 = -1q*1q
  and 6p*(-q) + q*p = 5pq