Maths qns (algebra)
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hehe. i nvr made such an easy one b4.Originally posted by launtpc:I bet YOUR balls (if you have one :lol
that you have made a mistake before.
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Whether or not this is true, only you yourself know, and your answer is there only to save your face.Originally posted by anhydrouscoppersulphate:hehe. i nvr made such an easy one b4.
So you have gotten 100 at everything since nursery? You come our from your mother then you can talk, and insult others at the level you have now?
I still tried. I at least tried to give a graphical workout, not like you who only gave the answers and insult others who try to give a more comprehensive solution. -
Like that also can flame each other
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He flamed me first, I am innocent!Originally posted by DriftingGuy:Like that also can flame each other
I won't reply that way. I believe both of us have contributed to the flamewar, instead of helping out... but then, the Great One said that he will not tolerate small mistakes, so let him do. I will not contribute anymore. -
Originally posted by DriftingGuy:Like that also can flame each other
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a simple maths question and an argument has ensued.
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so we should blame starpuppy..Originally posted by sinicker:a simple maths question and an argument has ensued. -
remind me never to ask a question in Chit Chat anymore...gee..u guys are swell frensOriginally posted by stellazio:so we should blame starpuppy.. 
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Result of having two clashing personalities...Originally posted by sinicker:a simple maths question and an argument has ensued. -
u shud go AA..Originally posted by StarPuppy:remind me never to ask a question in Chit Chat anymore...gee..u guys are swell frens -
yah. AA is the place. got "problems" doing maths mah.. so must go there!Originally posted by stellazio:u shud go AA.. -
It isn't clashing, it is diverse.Originally posted by DrTech:Result of having two clashing personalities... -
use the formular [ -b +- sqroot(b^2 - 4ac) ] / 2a
so u dont need to use trial and error -
ya lor..there's another method... completing the square
no need fer trial and error too..
2x²-3x-5=2(x²-1.5x-2.5)=2[x²-1.5x+(0.75²)-(0.75²)-2.5]
=2[(x-0.75)²]-6.125=0
(x-0.75)²=6.125/2=3.0625
x=+-1.75 + 0.75
so x=-1,x=2.5 -
mentally can lah.
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sinicker smart boy la..
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pls look at the shoutbox.Originally posted by papercut87:sinicker smart boy la.. -
The only guy who bothered to attempt to help plus post his answer gets all this unwanted comments >.< Tsk tsk...
Btw, you're asking to factorise the equation, not solve right..? -
yah loh wondering why so many ppl sovle itOriginally posted by Justy:The only guy who bothered to attempt to help plus post his answer gets all this unwanted comments >.< Tsk tsk...
Btw, you're asking to factorise the equation, not solve right..? -
chim chim...very chim...
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Say 2x^2 - 3x - 5 = 0
2(x^2 - (3/2)x - 5/2) = 0
2(x^2 - (3/2)x + (3/4)^2 - 9/16 - 5/2) = 0
2(x^2 - (3/2)x + (3/4)^2) = 49/8
(x - (3/4))^2 = 49/16
Hence,
x - (3/4) = 7/4 or x - (3/4) = -7/4
x = 5/2 or x = - 1
The factorization you want is of the form:
(2x - 5)(x + 1) (since the initial polynomial has coefficient 2 for the highest degree) -
don't have to do "Completing the Square". Just have to apply the cross multiply method to obtain the answer. It'll be much faster and will not make as much mistake as when doing "Completing the Square"Originally posted by CoolMyth:Say 2x^2 - 3x - 5 = 0
2(x^2 - (3/2)x - 5/2) = 0
2(x^2 - (3/2)x + (3/4)^2 - 9/16 - 5/2) = 0
2(x^2 - (3/2)x + (3/4)^2) = 49/8
(x - (3/4))^2 = 49/16
Hence,
x - (3/4) = 7/4 or x - (3/4) = -7/4
x = 5/2 or x = - 1
The factorization you want is of the form:
(2x - 5)(x + 1) (since the initial polynomial has coefficient 2 for the highest degree) -
I'm just suggesting another method.
As my lecturer always say, you're doing maths here. Knowing one method is not enough. You have to know all possible methods before you can say that you are doing maths.
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Nooo! Not solve, because behind the algebraic equation there is no "=0" so we cannot assume that.
We can only factorise.
x(2x-3)-5
Or can further factorise?