You quoted 2008 and 2009 as postive examples. But this doesn't prove my statement. My statement says "every year ... "Originally posted by JennTS:wtf? your an idiot.
if someone can show you a year that has 4 friday the 13ths/no friday the 13ths, will you change your question again?
oh...and your statement? i can easily prove it.
2008 has one friday the 13th. 2009 has 3 friday the 13ths.
if you were asking us to prove that its not true then...
its not possible, because theres a maximum and minimum limit to how many times a certain day can fall on a certain time of the month. out of 12 months, i dont think a certain day can fall on the 13th day all 12 times.
Like that you can only prove limited number of years. I want you to prove "every year"...Originally posted by DailyFreeGames.com:It's pretty simple to prove or disapprove this theroy with an application. As you know, there are applications that, when you specify a year, it will show the calender for that year, even if it's say, 1990 or 2025. Using this logic, we can have a program that runs from a specified year to another specified year and automatically count how many friday the 13th they are in that particular year. It's not totally accurate, but at least you can prove during say year 1000 to year 3000 there is/are how many friday the 13th to each year specifically. It's not totally accurate because it's only accurate as much as how you set the date range.
Hi I am talking about math, not computer program. If 1900-2100 don't have 4 such fridays, can you no such year exists???Originally posted by Gasfene:dude you are so bo liao but i think you should learn computer programming.
Write a computer code but insert the calendar from lets say 1900-2100. Then write an algorithm that says if(Friday=true) and (13=true), then printf(blah blah month year is a friday the 13'
Then count to see if there is a year with 4 friday the 13th.
dude count 200 years at a time. Then count 1700-1900 or something. If you used so much memory, chances are you need more computers and it takes hours to compute. Or your computers will just crash.Originally posted by zzzjjj2002:Hi I am talking about math, not computer program. If 1900-2100 don't have 4 such fridays, can you no such year exists???
and dude there is hardly any good maths formula for this. Different months have different days plus every 4 years got leap year. Every 100 years no leap year. Every 1000 years has leap year again.Originally posted by zzzjjj2002:Hi I am talking about math, not computer program. If 1900-2100 don't have 4 such fridays, can you no such year exists???
your statement says that every year has at least one Ft13th, and at most 3 Ft13ths, and you asked us to prove it. since its already true, theres no need to prove it.Originally posted by zzzjjj2002:You quoted 2008 and 2009 as postive examples. But this doesn't prove my statement. My statement says "every year ... "
Can you show me a year with 4 Fridays the 13th???