Originally posted by Mariner:
Q : A coil having a resistance of 20 ohms takes 950W from a 230V, 50Hz supply. Calculate
a.) The inductance and the power factor of the coil
b.) The reactive volt-amperes
* can someone explain what is
- power factor
- volt amperes
thxs
Assume:
1) RL circuit connected in series
2) Circuit in steady-state
Under steady-state,
Current, I = E/R = 230V/20ohms = ? A
Apparent Power, S = EI = 230 * ? = ?? VA
a) Power Factor, cos theta or pf = P/S = 950/?? = ??? (lag) (because circuit is inductive)
Reactive Power, Q = sqrt(S^2 - P^2) = sqrt(???^2 - 950^2) = ???? VAr (lag)
(Q in positive because inductive)
back to question a)
Q = I^2 * X (X is reactance of inductance)
X = Q / (I^2) = ???? / (?^2) = ????? ohms
Inductance, L = X / (2 * pi * frequency) = ????? / (2 * pi * 50) = ?????? H
b) Ans in part a. = ???? VAr (lag)
Explanation:
go to this site:
http://www.ibiblio.org/obp/electricCircuits/AC/AC_11.html#xtocid181751