It was banzie.Originally posted by banzie:One day John book a chalet and invite his friends... then hor when his friends arrived... he counted them one by one going into the chalet it was 3. So they stayed inside... lock the door for 3 days... no one went home or what... everyone stayed in the chalet.... play games lah do this and do that... then on the third day... He do a final count before booking out of the chalet... he foudn that the chalet has althougether 4 person? How come got one more person extra from the previous day counting!!???
x2Originally posted by mhcampboy:he counted himself.
your question tell the answer... he count the people going into the chalet which is 3 person...Originally posted by banzie:One day John book a chalet and invite his friends... then hor when his friends arrived... he counted them one by one going into the chalet it was 3. So they stayed inside... lock the door for 3 days... no one went home or what... everyone stayed in the chalet.... play games lah do this and do that... then on the third day... He do a final count before booking out of the chalet... he foudn that the chalet has althougether 4 person? How come got one more person extra from the previous day counting!!???
hmm whos the one?Originally posted by Tan Ah Teck:I see stupid people...
Seriously I found your jokes rather distasteful... Do you act this way in real life? You must have very little friends....Originally posted by Cystaire:It was banzie.
He finally managed to escape his evil ex-girlfriend, but now he must claim some insurance for missing parts.














Originally posted by PointBlue:Ok,
let no. of people in chalet when booking out = x
let C(n) be the statement that x^2+5=0
and since no. of people initially = 3,
let P(n) be the statement that x=(C(n.1).C(n.2))^1/2
Determining all possible combinations of n possible number of people, p,
Since,
Therefore, let S(x) = total no. of people with respect to np(1-p).n! no. of girls
* Given a subset U of A^n, when is U = V(I(U))?
* Given a set S of polynomials, when is S = I(V(S))?
Since,
Therefore if n(1-p)=1/n!
Hence, deriving the value of x via L'Hopital's rule,
Therefore, x=25.2
Conclusion: no. of people in the chalet after that =3
Err... my Maths fail... got simpler way of explaining?Originally posted by PointBlue:Ok,
let no. of people in chalet when booking out = x
let C(n) be the statement that x^2+5=0
and since no. of people initially = 3,
let P(n) be the statement that x=(C(n.1).C(n.2))^1/2
Determining all possible combinations of n possible number of people, p,
Since,
Therefore, let S(x) = total no. of people with respect to np(1-p).n! no. of girls
* Given a subset U of A^n, when is U = V(I(U))?
* Given a set S of polynomials, when is S = I(V(S))?
Since,
Therefore if n(1-p)=1/n!
Hence, deriving the value of x via L'Hopital's rule,
Therefore, x=25.2
Conclusion: no. of people in the chalet after that =3