Maths Qns

• Twincat

  5 Jan 07, 01:43

  Originally posted by papercut87:

  can use this eqn.. x = -b[+-]b^2-4ac / 2a where a = 10, b = 8, c = -18
  solve for x then.

  right cool thanks for reminder...
  
  Mmm think it is this ....
  x = -b[+-](b^2-4ac)^(0.5) / 2a