die riao :(
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i need help on physics on force. how to calculate the force etc..can anybody help me?
i oso need help in chemistry...on how to calculate mole etc. (mole still ok, but some qtns on find how many blahblah when there 12g of xx) -
check your textbook , all fomula are written there !! Dun be lazy
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i know formula, but i dunno how to apply
omgz! its all those diagonestic tests...=( i scare i cannot make it
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Force = Mass x Accelaration
find the object mass(kg) then times the accelarion value (m/s)
what do you mean by dont know how to apply -
really don't know want to help you lor not, these answers can be easily found from text and teachers
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Chemistry:
No of moles = mass/Mr
No of moles = volume/24dm^3
No of moles = conc x volume
Physics:
F = ma
....
erm..yeah.. -
this is a mole
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May the force be with you.
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go find your teacher for one-to-one consultation. no good teacher will reject a student in serious need of some help.
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k..i post 1 qtn here...
question copyright to my secondary sch.
a. Calculate the position of the centre of mass of the seat and plank. [3m]
b. If a victim of mass 75 kg is strapped onto the seat, calculate the additional force required to be applied on the counter-balance stone to balance the instrument. [2m] -
Originally posted by Hogzilla:May the force be with you.
I was about to post that
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engineering math?
knn, i hate such things. -
Congratulation!!
You earned a "Look down" from me. -
That's what my PC said to us (the whole company) when we first took IPPT as recruit.Originally posted by pervertboi:
I was about to post that -
this one is use moments not force de. anywya in this case force = mg mass x gravitational accelerration.Originally posted by Y_Shun:k..i post 1 qtn here...
question copyright to my secondary sch.
a. Calculate the position of the centre of mass of the seat and plank. [3m]
b. If a victim of mass 75 kg is strapped onto the seat, calculate the additional force required to be applied on the counter-balance stone to balance the instrument. [2m]
just balance the moments and i think you will get the answer.
and hor its mols i think -
how come moment question nowaday use example like torture tool ? Lowering the victim into cold water some more ,Originally posted by hisoka:this one is use moments not force de. anywya in this case force = mg mass x gravitational accelerration.
just balance the moments and i think you will get the answer.
and hor its mols i think -
btw whats mols?
if moment, can exprain n work it out for me anot? thxzz!! rly appreciate ur help!! -
taking moments on the plank about the pivot.
1*2 = (4-x)*1.2 then solve
then get x lor then you know the position of the c.g. le.
1 is the relative weight of the stone and 1.2 is the relative weight of the plank + seat( which acts thru the c.g.
erm 1 mol = a certain number of molecules of the molecule. the numebr is the alvagadro number -
a) clockwise moment = anticlockwise momentOriginally posted by Y_Shun:k..i post 1 qtn here...
question copyright to my secondary sch.
a. Calculate the position of the centre of mass of the seat and plank. [3m]
b. If a victim of mass 75 kg is strapped onto the seat, calculate the additional force required to be applied on the counter-balance stone to balance the instrument. [2m]
1000(10) x 2.0 = (4.0 - x) x 1200(10)
x = 2.33 m
b) Let M be the mass to balance
M x 2.0 = 75 x 4.0 + 1200 x 1.667
M = 1150 kg
Additional mass = 1000-1150 = 150 kg = 1500N of additional force -
a) clockwise moment = anticlockwise momentOriginally posted by Y_Shun:k..i post 1 qtn here...
question copyright to my secondary sch.
a. Calculate the position of the centre of mass of the seat and plank. [3m]
b. If a victim of mass 75 kg is strapped onto the seat, calculate the additional force required to be applied on the counter-balance stone to balance the instrument. [2m]
1000(10) x 2.0 = (4.0 - x) x 1200(10)
x = 2.33 m
b) Let M be the mass to balance
M x 2.0 = 75 x 4.0 + 1200 x 1.667
M = 1150 kg
Additional mass = 1000-1150 = 150 kg = 1500N of additional force -
Wait till you reach uni, learn how to solve such things using the superpower theorem, really its called the superpower theorem. Or maybe I remembered wrongly.
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i can give tuition..haha..
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ok remember..
Force = mass x acceleration ( farther = mother)
moment = force x perpendicular distance, in other words, force = moment /perpendicular distance
gravitational force = 9.81 or 10( both constant) x mass
as u could see, gravintational force is somehow like F=MA, just that the acceration is replaced by gravitational pull(9.81m/s^2 or 10m/s^2 depending on your syllabus)
so there are only 2 formulas you need to remember. the third one can be derive by replacing 9.81 or 10.
so.. when the question ask u about force topic, write these 2 formulas on the paper first (f=ma and moment = force* dist)
when u see mass given of the object in the qn, note the mass
if u see
acclereation, or falling object(falling object is at 9.81m/s^2 or 10m/s^2 unless resistance of air), note it .
so mass given, accleration given... u see the formula.. which one contains mass and acceleration? F=MA right?
do same as the moment formula too.
sometimes u have to play around with the forumla..
F=ma can also be A=f/m or M=f/a -
NB,
physics I return to my teachers liao.... -
i miss my physics teacher.