Originally posted by VagueHart:Sorry my math veh poor one..
Lets use * to denote the power of
EG 2*2 = 4 okk??
How to do the below question?
Solve the equation below giving your answers corrected to 3 significant figures
2lg(3x-2) = 5lg2.7
Izzit a quadratic equation in the end?
I do untill 9x*2-12x-139 = 0 den cannot do liao since 139 can only be formed by itself... >.<
Thanks in advance !~

Originally posted by VagueHart:Did that, i got the quad equation... its 9x*2-12x-139 which I think is impossible to do ask 139 is a number that can be divided only by itself and 1
Originally posted by Lorry`:hisoka's method also can be used, it's faster, but in terms of accuracy im not sure which's better![]()
Originally posted by VagueHart:why hisoka's method got y de?? typo?? sorry my math really veh terrible de
2.7 sorry typo, the metohd mroe important lahOriginally posted by VagueHart:why hisoka's method got y de?? typo?? sorry my math really veh terrible de
hmm.... okOriginally posted by the Bear:it's almost the same for the basic level...
you kind of lose a pile of stuff like complex numbers because lg(-ve number) isn't on the natural number line or something like that
Originally posted by Lorry`:hmm.... ok
are you a maths teacher?![]()
sec3 meh?Originally posted by Lorry`:i think he's sayin the end equation is 9x^2 - 12x - 139 = 0
and since 139 = 1* 139 only, then cannot solve, cant use cross method
hmm.. sec3 maths if i can rem ?
theres another method to solve? other than cross method,
maybe try the -b plusminus squareroot b^2 - 4ac over 2a method ?![]()
ya.. logarithm's sec 3 workOriginally posted by gLc:sec3 meh?
I sec4 now and i dont even understand the question...![]()