i forgot how already, but I think if you use complex numbers, you can solve it too........ you do the by parts, I do the complex numbers, then compare answer?Originally posted by tanjun:lol. The by parts method is really unexpected. It is the so called true power of the by parts.
Try this question. Very interesting too. Have to use tamago method to solve it.
thanks in advance, eagle.Originally posted by eagle:Differentiating it gives you the answer above, so I'm pretty sure it is correct. I shall now type it out on MS word, and post a screenshot of it here
Yep, this is another wayOriginally posted by HyuugaNeji:recursive formula ba... cos integrate or differentiate e^x always e^x.
so just take
INT e^x(cos x) =e^x(cos x) - INT e^x(-sin x)
=e^x(cos x) + INT e^x(sin x)
=e^x(cos x) + e^x(sin x) - INT e^x(cos x)
so 2 INT e^x (cos x) = e^x(cos x + sin x). then divide by 2.

This question or something similar came out for the ACJC prelims.Originally posted by tanjun:lol. The by parts method is really unexpected.
Try this question. Very interesting too. Have to use tamago method to solve it.

I used MS WordOriginally posted by HyuugaNeji:what program do you people use to get the integration function?
wow...kOriginally posted by eagle:I used MS Word
MS word too. You can go to help and type integration as the helping word. If the application supports mathematical function, they will display a list of instructions to help you with them.Originally posted by HyuugaNeji:what program do you people use to get the integration symbol?