Sorry folks.....a kinda tough maths question here

• ndmmxiaomayi

  6 Nov 05, 16:02

  This time, I edited. Confirmed liao.
  
  p = 5p/3 - sqrt((p(x + t)/x - t)
  p - 5p/3 = - sqrt((p(x + t)/x - t)
  (square both sides): p^2 - 10p^2/3 + 25p^2/9 = p(x + t)/x - t
  (X9 on both sides): 9p^2 - 30p^2 + 25p^2 = 9p(x + t)/x - t
  4p^2 = 9p(x + t)/x - t
  4p^2/9p = x + t/x - t
  4p/9 = x + t/x - t
  (cross multiply): 4px - 4pt = 9x + 9t
  4px - 9x = 9t + 4pt
  4px - 9x = t(9 + 4p)
  t = 4px - 9x/9 + 4p
  
  (simplify yourself)
• CoolMyth

  6 Nov 05, 16:03

  Originally posted by ndmmxiaomayi:

  I giving question 2 a try. Don't know if it is correct.
  
  p = 5p/3 - sqrt((p(x + t)/x - t)
  p - 5p/3 = - sqrt((p(x + t)/x - t)
  (square both sides): p^2 - 10p^2/3 + 25p^2/9 = p(x + t)/x - t
  (X9 on both sides): 9p^2 - 30p^2 + 25p^2 = 9p(x + t)/x - t
  4p^2 = 9p(x + t)/x - t
  4p^2/9p = x + t/x - t
  4p/9 = x + t/x - t
  4p(x - t)/9 = x + t
  t = 4p(x - t)/9 - x

  Still got t on right hand side.
• ndmmxiaomayi

  6 Nov 05, 16:05

  I know, so I am editing my reply. Wait a while.
• Mr Fugue

  6 Nov 05, 18:47

  all the handwriting so cute~!!

  Originally posted by CoolMyth:

  
  
  

  Originally posted by Texcoco II:

  
  
  How?

• nightzip

  6 Nov 05, 18:50

  Originally posted by Texcoco II:

  
  
  How?

  Steps: 1. bring down "a" to the left side
  2. sq. root both sides
  3. bring "-b" to become "+b" on the left side.
  
  Answer: M = (p/a)^(1/2) + b
  
  
• jay_rocks

  6 Nov 05, 18:52

  Originally posted by Texcoco II:

  
  
  How?

  p=a(m-b)^2
  p/a=(m-b)^2
  square root p/a + b = M
  
  ans
• jay_rocks

  6 Nov 05, 18:52

  double post
• deathscythe99

  7 Nov 05, 01:07

  Originally posted by Texcoco II:

  
  
  How?

  From above...
  
  p - (5p)/3 = -(square rt)( (p(x + t)) / (x - t) )
  
  -(2p / 3 )= -(square rt)( (p(x + t)) / (x - t) )
  
  2p/3 = (square rt)( (p(x + t)) / (x - t) )
  
  Squaring both sides,
  
  (2p/3)^2 = (p(x + t) ) / (x - t)
  
  4p/9 = (x+t) / (x-t)
  
  x(4p/9) - t (4p/9) = x + t
  
  x (4p/9 - 1) = t (4p/9 + 1)
  
  Therefore,
  
  t = [x (4p/9 - 1)] / (4p/9 +1)
  
• shade343

  7 Nov 05, 01:15

  Originally posted by dragg:

  try for fun
  
  p = a(M2 - b2)
  p = aM2 - ab2
  p/a = M2 - b2
  p/a + b2 = M2
  square root of p/a + b = M
  
  is it correct?
  

  Wrong.
  
  (a-b)^2 is not = (a^2-b^2)
• sexiest_studin_world

  7 Nov 05, 01:51

  Originally posted by Texcoco II:

  
  
  How?

  All of your solutions so boring sia. Make it more interesting like dis.
  
  Q. How to get 'eM (the ladies, your honey) from Pee, Ass and Bee?
  
  Solution.
  
  Pee = Ass ('eM - Bee)Squared
  
  You bringa Ass down, near Pee.
  After Pee is all a over your Ass, faira and Square, Root it outta.
  Den Add a Bee for honey, to your a Squarely Rooteda Pee over Ass a
  And a now a you've gotta 'eM.
  
  'eM=Bee + Squarely Rooted (Pee/Ass)
  
  
• ndmmxiaomayi

  7 Nov 05, 08:06

  Originally posted by sexiest_studin_world:
  
  
  All of your solutions so boring sia. Make it more interesting like dis.
  
  Q. How to get 'e[b]M (the ladies, your honey) from Pee, Ass and Bee?
  
  Solution.
  
  Pee = Ass ('eM - Bee)Squared
  
  You bringa Ass down, near Pee.
  After Pee is all a over your Ass, faira and Square, Root it outta.
  Den Add a Bee for honey, to your a Squarely Rooteda Pee over Ass a
  And a now a you've gotta 'eM.
  
  'eM=Bee + Squarely Rooted (Pee/Ass)
  
  [/b]

  Too chim. Catch no ball.
• Northwind

  7 Nov 05, 08:58

  Not sure how to write it out in this format, so...
  
  b + square root of p/a = M
  
  Erm...Nevermind. I mis read lol