Simple question. Me is a dragon baby, so I know this question. Only that it added till 97, not 100.Originally posted by LinLing:Oh, and if you can remember, was there any questions like:
1+2+3+4+5+6+7+8+9+10...................+98+99+100=??
The answer is this right..:
100x2-1=199.
Right?
Wah piang eh....Originally posted by X3Mi5t:Come let me teach u... Me LOVE math...
1+2+3+4+...+98+99+100=?? and 1+3+5+7+9+...+101=?? are all ARITHMETIC SEQUENCES. they have EQUAL differences between the numbers, like 2-1=1, 3-2=1 etc and 3-1=2, 5-3=2 etc.
So, this kind of sequences have a general formula to calculate for the sum one... It's n/2[2a+(n-1)d]. n is the nth term. a is the first term. then d is the common difference between the numbers, like 1 and 2 respectively.
So for the 1st sequence, nth term is the 100th term:
100/2[2*1+(100-1)*1]=5050
The 2nd sequence will be, nth term is 51st term:
51/2[2*1+(51-1)*2]=2601
So that's it!! Easy?
Just apply this formula. The thing will work out. BUT u must be very careful that the sequence has a common difference... as in the differences between the adjacent terms MUST be EQUAL before you apply this formula. Just take note of this pitfall and u'll be fine for this kind of qns.
~cheers~
ehh.. i think it was one of the qns during my year.. lol.. 2000 de..Originally posted by LinLing:Oh, and if you can remember, was there any questions like:
1+2+3+4+5+6+7+8+9+10...................+98+99+100=??
The answer is this right..:
100x2-1=199.
Right?
come on la, how the heck do u expect a 12 yr old to do power of 5 now...Originally posted by X3Mi5t:Oh... and by the way, if u're wondering whether there's any other kind of sequences, there is. I know of another one that is called GEOMETRIC sequence.
For this kind of sequence, the ratio between the terms must be the same. Ratio as in, the 2nd term divide by the 1st term = 3rd term divide by the 2nd term. This kind of sequence have a special formula: [a(1-r^n)]/(1-r). a, as usual, is the starting term. n is the nth term. r is the common ratio.
Let me give u an example:
1+3+9+27+...+81=??
First, look at the common ratio: 3/1=3, 9/3=3, 27/9=3. Hence, u can see that the common ratio for this sequence is 3. And the ratio is constant throughout, so u can safely use the formula. The nth term is the 5th term.
Therefore, [1(1-3^5)]/(1-3)=121.
ok, just like that. that's all.... just remember: equal ratio.
kan chime!Originally posted by ndmmxiaomayi:Simple question. Me is a dragon baby, so I know this question. Only that it added till 97, not 100.
Add 1 to 10 together. What's the answer?
Next add 11 to 20. What's the answer again?
Add 21 to 30. What's the answer?
See a pattern?
The last 2 digits will always be 55 and as the pattern goes on, the hundreds digit increase by one.
So, final answer will be 55+155+255+355+455+555+655+755+855+955 = 5050.
study smart not hardOriginally posted by LinLing:VERY HARD.
please. 250 is a shitty score if you want to consider nygh. i think you should aim for RGS. get at least 260. that would be an A* for everything.Originally posted by jayellefull:250 and above is high...you are someone who does well in school all along? just remember to pace yourself. the worst thing that will happen is losing steam around the PSLE because you overstretched yourself in the prelims and midyears..honey, psle is just the start...you have o levels and a levels and perhaps degree and honours to take next time, dont worry too much
Hey do consider NYGH ...
other schools that you could aim for are rvhs, mgs and scgs though each has its own different reputation, depends on your liking
you know what when i was 12 i didn't even know what a forum was
wtf? that looks like permutations.Originally posted by X3Mi5t:Come let me teach u... Me LOVE math...
1+2+3+4+...+98+99+100=?? and 1+3+5+7+9+...+101=?? are all ARITHMETIC SEQUENCES. they have EQUAL differences between the numbers, like 2-1=1, 3-2=1 etc and 3-1=2, 5-3=2 etc.
So, this kind of sequences have a general formula to calculate for the sum one... It's n/2[2a+(n-1)d]. n is the nth term. a is the first term. then d is the common difference between the numbers, like 1 and 2 respectively.
So for the 1st sequence, nth term is the 100th term:
100/2[2*1+(100-1)*1]=5050
The 2nd sequence will be, nth term is 51st term:
51/2[2*1+(51-1)*2]=2601
So that's it!! Easy?
Just apply this formula. The thing will work out. BUT u must be very careful that the sequence has a common difference... as in the differences between the adjacent terms MUST be EQUAL before you apply this formula. Just take note of this pitfall and u'll be fine for this kind of qns.
~cheers~
Err... What's this language? And what it means?Originally posted by 798:kan chime!
Originally posted by LinLing:
As I want to get ready for my PSLE in advance, can the older ones please tell me some tips and some good revision books to use? How did you study and maybe suggest some good sec schools?
I really need it!! (My brother said he don't know. =P)
And if it is possible, ALL THE INFORMATION ABOUT PSLE.
Aiyo.Originally posted by ^tamago^:and come, let me teach you, "I before E, except after C."