Maths Problem
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1) For any real number x:
x² - x² = x² - x²
2) Factoring both sides in two different ways:
x² + x² - x² - x² = x² - x²
(x - x)(x + x) = x(x - x)
3) Dividing both sides by (x - x):
(1)(x + x) = x(1)
4) Which is:
2x = x
5) Since this is valid for any value of x, we can plug in x = 1.
2 = 1
but....... how can 2 be equals to 1?
come, see who can explain why.... -
is this solution correct or not, to begin with?
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Originally posted by ^tamago^:1) For any real number x:
x² − x² = x² − x²
2) Factoring both sides in two different ways:
(x − x)(x + x) = x(x − x)
3) Dividing both sides by (x − x):
(1)(x + x) = x(1)
4) Which is:
2x = x
5) Since this is valid for any value of x, we can plug in x = 1.
2 = 1
but....... how can 2 be equals to 1?
come, see who can explain why....
..haha..duinnno..
but doesnt this should be in the math forum? -
there's a reason why it's wrong, just wan to see if anyone noes.....Originally posted by rainee:is this solution correct or not, to begin with? -
is it this?.Originally posted by ^tamago^:1) For any real number x:
x² - x² = x² - x²
2) Factoring both sides in two different ways:
x² + x² - x² - x² = x² - x²
(x - x)(x + x) = x(x - x)
3) Dividing both sides by (x - x):
(1)(x + x) = x(1)
4) Which is:
2x = x
5) Since this is valid for any value of x, we can plug in x = 1.
2 = 1
but....... how can 2 be equals to 1?
come, see who can explain why....
since u have done it to one side of the equation..u should do it to the other side of the equation..
dunno...just a guess -
indirectly related to mathematics?
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cannot divide by (x-x)
X - x = 0
division by zero => undefined -
i tot by 2 the answer = 0 liao?Originally posted by ^tamago^:1) For any real number x:
x² - x² = x² - x²
2) Factoring both sides in two different ways:
x² + x² - x² - x² = x² - x²
(x - x)(x + x) = x(x - x)
3) Dividing both sides by (x - x):
(1)(x + x) = x(1)
4) Which is:
2x = x
5) Since this is valid for any value of x, we can plug in x = 1.
2 = 1
but....... how can 2 be equals to 1?
come, see who can explain why.... -
yes. tat's it. solved.Originally posted by kalangkabo:cannot divide by (x-x)
X - x = 0
division by zero => undefined
awareness for those who does algebra for a living.
case closed. -
Cannot divide by x-x la. Will have division by zero
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number theory.Originally posted by Janedoeslove:indirectly related to mathematics? -
This is not number theory.Originally posted by ^tamago^:number theory. Just simple algebra. -
pai seh...my maths not good...but i thot:Originally posted by ^tamago^:1) For any real number x:
x² - x² = x² - x²
2) Factoring both sides in two different ways:
x² + x² - x² - x² = x² - x²
(x - x)(x + x) = x(x - x)
3) Dividing both sides by (x - x):
(1)(x + x) = x(1)
4) Which is:
2x = x
5) Since this is valid for any value of x, we can plug in x = 1.
2 = 1
but....... how can 2 be equals to 1?
come, see who can explain why....
=> x² - x² = x² - x²
=> 0 = 0
Isn't it? -
this i why i dont like maths
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since first step already found out x=0,
den other steps only make u blur.. -
Originally posted by Janedoeslove:since first step already found out x=0,
den other steps only make u blur..
That's what i thought...why the h3ll still need to factorise... -
no ar, first step says, for any real number x. x can be any number.
this line is also true
(x - x)(x + x) = x(x - x)
i can put x=1, it is still a valid mathematical statement. 0 × 0 = 0 × 0 = 0
but when i divide by 0 the whole statement becomes invalid, as illustrated by the resulting x + x = x -
cos got division by zero lah, tat's the part about number theory...Originally posted by CoolMyth:This is not number theory. Just simple algebra. -
Number theory where got division by zero one?Originally posted by ^tamago^:cos got division by zero lah, tat's the part about number theory...
Number theory basically talks about infinitude of primes and all that crap. This is really just simple algebra as far as I see it. -
huh?Originally posted by ^tamago^:no ar, first step says, for any real number x. x can be any number.
this line is also true (x - x)(x + x) = x(x - x)
i can put x=1, it is still a valid mathematical statement. 0 × 0 = 0 × 0 = 0
but when i divide by 0 the whole statement becomes invalid, as illustrated by the resulting x + x = x
let x=1 or 2 or 3 or 9999999999 also same wat...
x-x=0 -
it is. the qn is just asking u to prove that left hand = right hand. doesn't matter 0=0 or 1=1 or -1=-1Originally posted by dcx:pai seh...my maths not good...but i thot:
=> x² - x² = x² - x²
=> 0 = 0
Isn't it?
btw nicely done whoever solved this. -
1) For any real number x:
x² - x² + x = x² - x² + x
2) Factoring both sides in two different ways:
x² + x² - x² - x² + x = x² - x² + x
(x - x)(x + x) + x = x(x - x) + x
3) Dividing both sides by (x - x):
(x + x) + [x/(x - x)] = x + [x/(x - x)]
4) Minus both sides by [x/(x - x)]:
x + x = x
2x = x
5) Since this is valid for any value of x, we can plug in x = 1.
2 = 1 -
prove? lagi easier....Originally posted by jenn_y:it is. the qn is just asking u to prove that left hand = right hand. doesn't matter 0=0 or 1=1 or -1=-1
btw nicely done whoever solved this.
i've 1 apple and mary has 1 apple. I ate 1 apple and mary ate 1apple...how many apples left?
1 - 1 = 1 - 1
0 = 0 -
aiyo maths ar
ch0i no gud in maths ar
so canot tolong -
ch0i sound like flippino maid....
