did you? i didnt; just made up a value that is somewhere near the value which i got for the first method. and i drew a curve for the second qns.Originally posted by morningglory:did you manage to find it in the end?
question 2 should be a straight line.
thats a relief! how did you do?Originally posted by gohby:Its a curve. All the teachers say its a curve. However, the curve is not very distinct. The curve is due to friction. The higher the velocity, the more the friction ......
Speaking of which, dont worry, a lot of people screw up too![]()
should be a straight line lah. if not u tell me how to find gradient? My teachers said it is a straight line.Originally posted by gohby:Its a curve. All the teachers say its a curve. However, the curve is not very distinct. The curve is due to friction. The higher the velocity, the more the friction ......
Speaking of which, dont worry, a lot of people screw up too![]()
did you make sure the pinhead is in the centre of the mirror and lens? and you have to look directly down on the pinhead. cannot look from slanted angle else you cant see the image. then move the pin up or downOriginally posted by jaydunkfull:did you? i didnt; just made up a value that is somewhere near the value which i got for the first method. and i drew a curve for the second qns.
is it me or is the paper difficult? how come it seems so easy for all of you? darn, i must be stupid. wan le...wan le...
i got 15 for both.Originally posted by Orange*Asterisk:What's the focal length?
I got 12.5 for method 1 and 15 for method 2.
Originally posted by TwinTurbo_Supra:i got 15 for both.i think im screwed.
but the thickness of the lens makes alot of diff leh. for 0.4 u get 15, 0.5 u get 12.
FYI, I drew a straight line. I understand what u mean by "cannot find gradient" cos I thought the same way too. As a result, I was not very convinced with my teachers' answers.Originally posted by TwinTurbo_Supra:should be a straight line lah. if not u tell me how to find gradient? My teachers said it is a straight line.
the friction is negligible at such slow speed and the area in contact with the rulers is so small.
i got a curve too. i cheated. i calculated the difference of the time interval btw every 5 cm and ploted the graph :pOriginally posted by mystiv:curve..? hmm...
it's a curve. since acc of free fall is at constant, integrate a constant graph will eventually get u a curve.Originally posted by Classyfied:it should be a straight line...best fit straight line...
or else they will nt ask u calculate the gradient..
this year the examiners very fukker..never say draw wad type of curve shape...
my teacher even confirmed with me that it is a str line.
=) so cheers
actually ytd one not that hard la...
except one question....
wad did u all say abt the image?
is it diminished or same size or enlarged?
i wrote same size leh...
haiz.![]()
theoratically it's a curve, because the marble reaches terminal velocity.Originally posted by Orange*Asterisk:it's a curve. since acc of free fall is at constant, integrate a constant graph will eventually get u a curve.
finally someone whos singing the same note as me ~Originally posted by vice_edge:i plotted a best fit straight line . mirror question was a pain in the ass screw physics la
cannot 90 cm...Originally posted by TwinTurbo_Supra:theoratically it's a curve, because the marble reaches terminal velocity.
but u think the marble can reach terminal velocity within 90 cm?